
Our common denominator is going to be 5x(x+2) so you have to multiply each part of the equation so that they each have the same denominator. Multiply the first section by 5x, the second by 5(x+2), and the third by x+2. After all of that your new equation will look like this:
![15x/[5x(x + 2)] - (5x + 10)/[5x(x + 2)] = (x + 2)/[5x(x + 2)]](http://www.purplemath.com/modules/rational/solve10.gif)
At this point, the denominators are the same. So do they really matter? Not really (other than for saying what values x can't be). So cross out the denominators and you have an equation that looks like: 15x–(5x + 10) =x+2. The rest is cake we are trying to get x alone so you solve like a regular equation. First distribute. Then The rest looks like:
15x – (5x + 10) = x +2
10x – 10 = x + 2
9x = 12
x = 12/9 = 4/3
Since x = 4/3 won't cause any division-by-zero problems in the fractions in the original equation, then this solution is valid. And that's all there is to it!
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